12j^2=-64+76j

Solution for 12j^2=-64+76j equation:

12j^2=-64+76j

We move all terms to the left:

12j^2-(-64+76j)=0

We add all the numbers together, and all the variables

12j^2-(76j-64)=0

We get rid of parentheses

12j^2-76j+64=0

a = 12; b = -76; c = +64;
Δ = b2-4ac
Δ = -762-4·12·64
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-76)-52}{2*12}=\frac{24}{24}
=1
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-76)+52}{2*12}=\frac{128}{24}
=5+1/3
$